(3x-4)(x^3+3x-6)=0

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Solution for (3x-4)(x^3+3x-6)=0 equation: 


Simplifying
(3x + -4)(x3 + 3x + -6) = 0

Reorder the terms:
(-4 + 3x)(x3 + 3x + -6) = 0

Reorder the terms:
(-4 + 3x)(-6 + 3x + x3) = 0

Multiply (-4 + 3x) * (-6 + 3x + x3)
(-4(-6 + 3x + x3) + 3x * (-6 + 3x + x3)) = 0
((-6 * -4 + 3x * -4 + x3 * -4) + 3x * (-6 + 3x + x3)) = 0
((24 + -12x + -4x3) + 3x * (-6 + 3x + x3)) = 0
(24 + -12x + -4x3 + (-6 * 3x + 3x * 3x + x3 * 3x)) = 0
(24 + -12x + -4x3 + (-18x + 9x2 + 3x4)) = 0

Reorder the terms:
(24 + -12x + -18x + 9x2 + -4x3 + 3x4) = 0

Combine like terms: -12x + -18x = -30x
(24 + -30x + 9x2 + -4x3 + 3x4) = 0

Solving
24 + -30x + 9x2 + -4x3 + 3x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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